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...tube, one at a time, add 3 drops of liver extract containing catalase. Give the test tube a small shake. 6. Observe the tube for evidence of activity; the release of O2 gas resulting in bubbles. 7. Measure, using the small ruler, the height of the bubble column from the top of the liquid in the test tube. 8. Record your results in mm in the data table next to the corresponding temperature of the water bath. Data Presentation: Group Ice Bath (3C) Room Temp (21C) Warm water (43C) Hot water (83C) Boiling (101C) 1 50mm 35 45 3 0 2 17 20 85 0 0 3 4 47 52 0 3 4 8 25 73 3 2 5 35 40 45 5 2 6 3 40 45 2 1 7 35 40 43 14 0 8 30 30 60 10 3 9 41 41 7 36 0 10 15 35 46 14 39 Avg. ht. 23.8 35.3 50.1 8.75 5 Mathematical Calculations: T-Test: 1) Array 1 = ice water: 23.8 Array 2 = room temp: 35.3 T-Test value = 0.015 100 0.015 = 98.5% confidence Yes, there is a significant difference 2) Array 1 = ice water: 23.8 Array 2 = warm water: 50.1 T-Test value = 0.002 100 0.002 = 99.8% confidence Yes, there is a significant difference 3) Array 1 = ice water: 23.8 Array 2 = hot water: 8.75 T-Test value = 0.053 100 0.053 = 94.6% confidence No, there isnt a significant difference 4) Array 1 = ice water: 23.9 Array 2 = boiling water: 5 T-Test value = 0.018 100 0.018 = 98.2% confidence Yes, there is a significant difference Conclusions: 1. The normal body temperature for a human is 37 degrees Celsius. I estimated the internal body temperature for a chicken to be about 43 degrees Celsius. I estimated this because it is the temperature where enzymes from a chicken worked best in the lab. Temperature has an enormous affect on the effectiveness of enzymes. This is one reason why it is extremely important for animals to maintain homeostasis. 2. 3. The graph illustrates the importance of temperature in rel...